標題:
F.5 phy circular motion
發問:
Picture of the experiment: http://postimg.org/image/3nxsazqj9/ Question: http://postimg.org/image/eosxg0is5/ I want to ask how to prove the equation and what is the meaning of b. Why the perpendicular forces are equal? Thank you!
最佳解答:
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The motion of the sticky tape is given by, T.cos(theta) + Ff = mR.w^2 where T os the tension in the threadc, (theta) is the angle between the thread and the horizontal, R is the radius of the circular motion, w is the angular speed. Ff is the friction acts on the thread by the rim of the glass tube Since, T = Mg, R = (L+a).cos(theta), where a is the radius of the sticky tape w = 2.pi/(t/20) = 40.pi/t thus, Mg.cos(theta) + Ff = m.Lcos(theta).[40.pi/t]^2 i.e. Mg +Ff = 1600.(pi)^2.m(L+a)/t^2 Mg = 1600(pi)^2.m(L+a)/t^2 - Ff The constant b is thus the frictional force Ff
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