close
標題:
f5數學題一問?
發問:
given r is root of equation x^2-3x-5=0,find value of r^5-3r^4-5r^3+2r^2-6r
最佳解答:
此文章來自奇摩知識+如有不便請留言告知
r is a root of the equation x^2-3x-5=0 When x=r r^2-3r-5=0 r^5-3r^4-5r^3+2r^2-6r =(r^2-3r-5)r^3+2r^2-6r =0Xr^3+2r^2-6r =2r^2-6r =2r^2-6r-10+10 =2(r^2-3r-5)+10 =2X0+10 =10
其他解答:
文章標籤
全站熱搜
留言列表
